I'm a user of ClinSerts® CLHM.
The pull-out strength can be calculated from the formula in the catalogue.

Pull-out-strength for ClinSerts®, Calculation is as follows:
Pull-out-strength(N) = shear engagement (mm2) x ultimate shear strength of parent material (N/mm2)

Shear engagement areas are shown on the ClinSerts® data sheets, only valid for full installed
ClinSerts®

The questions are :

This would therefore imply that the part receiving the insert constitutes the “fuse” part.

• Is this the correct way to understand it?
• Are the reinforced series clinserts able to receive class 8.8 and 10.9 screws tightened to the torque of standard NF 25-030? And this without the risk of deforming them plastically?
• What are the limitations of this approach? Is it only applicable when the keensert is mounted in steel type S235 or in an aluminum alloy?
• What about high strength steel? Does the screw become the fuse? Or is it the Clinsert?

Thank you in advance for your help.

Technical reply :

Yes this is in general right.
If the ClinSerts® is installed into aluminum a stainless steel or steel screw (8.8 quality) should be tightened with the usual torque for these types of screws.

A ClinSerts® is made to reinforce softer materials like aluminum. In steel or even high strength steel the ClinSerts® will become the weakest part so it does not really make sense to use a ClinSerts® (for reinforcing, some customers use it to have a quick replacement of the thread, for example when sand is involved)
There are ClinSerts® with higher strength like A286, 316L and Inconel that might make sense in these cases.